偶看新闻白话二十四史txt百度云:标准的宝塔线————股市骑兵编写
来源：百度文库 编辑：偶看新闻 时间：2024/04/29 01:03:02
标准的宝塔线————股市骑兵编写
c1:=c;o1:=o;
for i=1 to DATACOUNT do begin
if i=1 then begin
if c1[i]>o1[i] then begin
x[i]:=1;cc1[i]:=c1[i];oo1[i]:=o1[i];
end;else
if c1[i]x[i]:=4;cc4[i]:=c1[i];oo4[i]:=o1[i];
end;else begin
x[i]:=0;
cc1[i]:=c1[i];oo1[i]:=o1[i];
cc4[i]:=c1[i];oo4[i]:=o1[i];
end;end;
if i=2 then begin
if x[i-1]=1 or x[i-1]=0 then begin
if c1[i]>cc1[i-1] then begin
x[i]:=1;//阳
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else
if c1[i]x[i]:=3;//阳平下
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else begin
x[i]:=2;//阳平
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
if x[i-1]=4 or x[i-1]=0 then begin
if c1[i]x[i]:=4;//阴
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else
if c1[i]>oo4[i-1] then begin
x[i]:=6;//阴平上
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else begin
x[i]:=5;//阴平
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;end;
if i>2 then begin
if x[i-1]=1 then begin
if c1[i]>cc1[i-1] then begin
x[i]:=1;
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else
if c1[i]x[i]:=3;
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else begin
x[i]:=2;
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
if x[i-1]=2 then begin
if c1[i]>cc1[i-1] then begin
x[i]:=1;
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else
if c1[i]x[i]:=3;
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else begin
x[i]:=2;
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
if x[i-1]=3 then begin
if c1[i]>oo1[i-1] then begin
x[i]:=6;
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else
if c1[i]x[i]:=4;
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else begin
x[i]:=5;
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;
if x[i-1]=4 then begin
if c1[i]x[i]:=4;
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else
if c1[i]>oo4[i-1] then begin
x[i]:=6;
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else begin
x[i]:=5;
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;
if x[i-1]=5 then begin
if c1[i]>oo4[i-1] then begin
x[i]:=6;
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else
if c1[i]x[i]:=4;
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else begin
x[i]:=5;
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;
if x[i-1]=6 then begin
if c1[i]x[i]:=3;
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else
if c1[i]>cc1[i-1] then begin
x[i]:=1;
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else begin
x[i]:=2;
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
end;end;
STICKLINE(x and cc1>0 and oo1>0,cc1,oo1,7,1);
STICKLINE(x and cc4>0 and oo4>0,cc4,oo4,7,0);
x,LINETHICK0;
c1:=c;o1:=o;
for i=1 to DATACOUNT do begin
if i=1 then begin
if c1[i]>o1[i] then begin
x[i]:=1;cc1[i]:=c1[i];oo1[i]:=o1[i];
end;else
if c1[i]
end;else begin
x[i]:=0;
cc1[i]:=c1[i];oo1[i]:=o1[i];
cc4[i]:=c1[i];oo4[i]:=o1[i];
end;end;
if i=2 then begin
if x[i-1]=1 or x[i-1]=0 then begin
if c1[i]>cc1[i-1] then begin
x[i]:=1;//阳
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else
if c1[i]
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else begin
x[i]:=2;//阳平
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
if x[i-1]=4 or x[i-1]=0 then begin
if c1[i]
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else
if c1[i]>oo4[i-1] then begin
x[i]:=6;//阴平上
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else begin
x[i]:=5;//阴平
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;end;
if i>2 then begin
if x[i-1]=1 then begin
if c1[i]>cc1[i-1] then begin
x[i]:=1;
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else
if c1[i]
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else begin
x[i]:=2;
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
if x[i-1]=2 then begin
if c1[i]>cc1[i-1] then begin
x[i]:=1;
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else
if c1[i]
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else begin
x[i]:=2;
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
if x[i-1]=3 then begin
if c1[i]>oo1[i-1] then begin
x[i]:=6;
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else
if c1[i]
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else begin
x[i]:=5;
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;
if x[i-1]=4 then begin
if c1[i]
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else
if c1[i]>oo4[i-1] then begin
x[i]:=6;
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else begin
x[i]:=5;
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;
if x[i-1]=5 then begin
if c1[i]>oo4[i-1] then begin
x[i]:=6;
cc4[i]:=oo4[i-1];oo4[i]:=cc4[i-1];
cc1[i]:=c1[i];oo1[i]:=oo4[i-1];
end;else
if c1[i]
cc4[i]:=c1[i];oo4[i]:=cc4[i-1];
end;else begin
x[i]:=5;
cc4[i]:=cc4[i-1];oo4[i]:=c1[i];
end;end;
if x[i-1]=6 then begin
if c1[i]
cc1[i]:=cc1[i-1];oo1[i]:=oo1[i-1];
cc4[i]:=c1[i];oo4[i]:=oo1[i-1];
end;else
if c1[i]>cc1[i-1] then begin
x[i]:=1;
cc1[i]:=c1[i];oo1[i]:=cc1[i-1];
end;else begin
x[i]:=2;
cc1[i]:=cc1[i-1];oo1[i]:=c1[i];
end;end;
end;end;
STICKLINE(x and cc1>0 and oo1>0,cc1,oo1,7,1);
STICKLINE(x and cc4>0 and oo4>0,cc4,oo4,7,0);
x,LINETHICK0;
折纸——怎样折宝塔
请问，关于赏金骑兵2——库珀的复仇出来了吗？
孟庆茂—《应用心理学》的编写人
宝塔诗的解法
怎样编写程序：1—100之间偶数的和?
请问我国股市2006年1月——6月的走势
编写VB程序——急！！！
C语言——编写函数
宝塔线进行操作的方法和定义 证券习题
欧洲骑兵和中国骑兵的区别
股市分析软件是用什么语言编写的?如果要编写需要涉及到那些方面的知识?
骑兵的速度 素质
《最后的骑兵》
最大的骑兵战役
中国古代的骑兵战术？
ITU—TG.703 标准
C语言有什么标准的编写工具吗？
标准编写系统有没有更新的版本
点解打不开C语言编写程序，即MS—DOC方式
请教高手欧姆龙CPM1A—20的程序编写如何实现24小时定时
请教高手欧姆龙CPM1A—20的程序编写如何实现24小时定时
请问宝塔型的缝纫线的线壳哪里有买?
为什么佛教的宝塔层数都是奇数?
宝塔山邮票哪年发行的